Comments on: Show All with a Range Parameter Query

By: Doug Jenkins

Doug Jenkins — Sat, 13 Oct 2007 04:18:00 +0000

Jeffrey - you use the = Range("rng") form where you are referring to a worksheet range with the name "rng", but in the case of a function you have declared it as a range, so it is already a range object.

Try this:

Function ReadCell(rng As Range, Rtype As Long) As Variant
Application.Volatile (True)
Select Case Rtype
Case 1
ReadCell = rng.Value
Case 2
ReadCell = rng.Address
Case 3
ReadCell = rng.Font.FontStyle
Case 4
ReadCell = rng.Font.Name
Case 5
ReadCell = rng.Height
Case Else
ReadCell = "Rtype is defined for 1 to 5 only"
End Select
End Function

By: Jeffrey pattavina

Jeffrey pattavina — Fri, 12 Oct 2007 20:12:00 +0000

I cannot get a VBA function to accept a range variable: The following function will not work. I want rng to be a cell range (i.e., A1)

Function ReadCell(rng As Range)
Application.Volatile (True)
ReadCell = Range("rng")
End Function

By: Rob van Gelder

Rob van Gelder — Fri, 28 Oct 2005 22:41:00 +0000

Much as what JK said...

Use the 'like' operator in your SQL statement.

select CompanyName, City from customers where city like ?

Range examples:
London
B%
B_r%

By: jkpieterse

jkpieterse — Fri, 28 Oct 2005 17:51:00 +0000

If you are using a like criterium (part of the SQL below):

WHERE (ReferenceNumber Like '%' & ? & '%')

and you enter the percent sign in the linked cell, you also get all results back.