Comments on: Replacing the Analysis Toolpak Addin – Part 3

By: David

David — Thu, 15 Apr 2010 20:07:00 +0000

Hi guys,
I use this hex to decimal converter and this decimal to hex converter to convert data
They are pretty good!
Hope this help
David

By: priquas

priquas — Tue, 24 Feb 2009 09:18:00 +0000

Still in 2009 this information is of much value, solving a big problem I'd encountered.

Moreover, the proposed approach has opened my mind to other applications.

By: Leion

Leion — Fri, 31 Oct 2008 10:08:00 +0000

I do not it why the replacement formula works for the DEC2BIN, can you explain ?

By: scott

scott — Tue, 20 May 2008 20:30:00 +0000

This information has saved me HOURS if not DAYS.
Thank you.

By: Frank_K

Frank_K — Thu, 05 Jul 2007 16:45:00 +0000

Thank you for your quick input and it working.

By: Dick Kusleika

Dick Kusleika — Wed, 04 Jul 2007 16:20:00 +0000

Frank: =HEX2DEC(TEXT(A1,"00?)&TEXT(A2,"00?))

Your value in A2 is a number, not a string. Excel is concatenating 10 and 1, not 10 and 01. It's only the formatting in A2 that makes it appear as 01.

By: Frank_K

Frank_K — Wed, 04 Jul 2007 00:20:00 +0000

I need some help for Excel Hex2Dec function!
I have value "10? in Cell A1 and "01? in A2.
When I use Hex2Dec(A1&A2) and I expect to = Hex2Dec ("1001?).
But Excel translate to Hex2Dec("101?).
The question is how to get Excel to translate "1001?.
Any help will be very gratful.

By: Dick Kusleika

Dick Kusleika — Wed, 07 Feb 2007 01:30:00 +0000

Brian: DEC2BIN returns a number. Excel can't handle numbers greater than 15 significant digits, so if your BIN looks like a number that has that many significant digits, it will return the wrong result. Note that 32768 and 32769 return the same result because the last 1 in 32769 would be the 16th significant digit. In your example, there are 17 significant digits, so the last two are simply replaced with zeros.

Ideally, this function would return a string to avoid this problem. Unfortunately, Excel doesn't let you concatenate strings inside of array formulas. I can't think of a good alternative. Hopefully someone can think of something or at least change the formula to return an error instead of incorrect results. In the mean time, use it with caution and beware of the issue.

By: Brian

Brian — Tue, 06 Feb 2007 21:24:00 +0000

Hi Frank,

I've noticed an issue with your DEC2BIN replacement function(assuming of course that I'm using it correctly).

What I really need is Hex to Bin conversion, so as suggested I use your HEX2DEC and DEC2BIN. When I start with a number like 138d7, it converts to decimal fine (80087), but the final step gives me 10011100011010100 ( jeez I hope I typed that right!).

That binary figure is actually 80084 dec or 138d4 hex. I've lost 3! That can be easily seen since the last hex digit of "7? should be "0111? in bin, not "0100?.

Is it me?
Thanks,
Brian

By: Marc

Marc — Tue, 12 Dec 2006 02:21:00 +0000

I'm converting binary numbers with up to 32 bits. That's 4,286,578,691 in decimal.

I have no problems going from BIN2DEC, but the DEC2BIN formula stops working at about 265,000,000. I get a #NUM! error.

Any ideas?