Comments on: Concatenating and splitting strings

By: Michael

Michael — Tue, 01 Dec 2009 19:13:00 +0000

Saket -

Assuming you have the date as a true date (a number, not text looking like a date) then use the DAY(date), MONTH(date) and YEAR(Date) functions.

If the date is text, but in a date format Excel understands, then use the DATEVALUE(text) function first, inside the DAY(), MONTH(), and YEAR() functions.

If it's not a format Excel understands, provide an example and we'll go from there.

...mrt

By: Saket Kumar

Saket Kumar — Mon, 30 Nov 2009 05:39:00 +0000

Hi.... I have a similar problem.
I want to split the date into date, month and year.
can anyone tell me how to do that?

Thanks in advance!!

By: Yume

Yume — Fri, 04 Jul 2008 06:02:00 +0000

Hi,

Thanks for the tip. But I have some question. I want to split a string like this "Hello World" into "HW" or "Go go go" into "GGG" in a cell, "Nothing gonna change my love for you" into "NGCY", what function should I use?

By: Ellen

Ellen — Mon, 18 Feb 2008 19:43:00 +0000

Could you help me to convert: 123456789,1234.jpg
to: "123456789?,"1234.jpg"

Can I use concatenate formula?

Thanks.

By: Judith

Judith — Tue, 12 Feb 2008 23:06:00 +0000

Thanks for the concatenating strings tip. It worked great to concatenate multiple categories from an row array that included blank cells. I used a comma separator, not the dash, to make them suitable for upload into Outlook categories as part of an overall contact upload.

By: Phil

Phil — Tue, 18 Dec 2007 08:19:00 +0000

I thought I'd just quickly post the original solution that I'd devised for this problem - some of you may find it amusing in its clumsiness.

Say our 6 digit number (A1) was 654,321. Of the 'single digit' cells, the first one (C1) was simply Rounddown(A1/100000) to one digit. The second cell from the left was Roundown (A1-(C1*100000)/10000) and so on, stripping off the digits one by one by rounding down and dividing. Very very messy by the time I got to the 6th cell.

Phil

By: Phil

Phil — Tue, 18 Dec 2007 07:44:00 +0000

Thanks all;

I've got with a variation on the LEN function suggestion: works treat. I'd never heard of that function before, so thanks for that!

Phil

By: fzz

fzz — Mon, 17 Dec 2007 22:30:00 +0000

I replied to this last week, but this site must not have liked my escaped HTML characters. I'll try again.

It's possible to handle embedded spaces in the text values if you're willing to put up with long formulas.

=MID(IF(A1="","","-"&A1)&IF(B1="","","-"&B1)
&IF(C1="","","-"&C1)&IF(D1="","","-"&D1),2,32768)

By: fzz

fzz — Mon, 17 Dec 2007 22:23:00 +0000

@Dan

There's an easier approach. With value in A1, enter this formula in B1 then fill B1 right.

=MID(TEXT($A1,"000000?),COLUMNS($B1:B1),1)

By: Dan

Dan — Mon, 17 Dec 2007 20:51:00 +0000

Best thing to do would be to create a 6-digit string and then select your digit.

=mid(CONCATENATE(REPT("0?,6-LEN(A1)),A1),C1,1)

A1 contains the number. C1 contains the digit number that you want...