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	<title>Comments on: Rounding Worksheet Funtions</title>
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	<link>http://www.dailydoseofexcel.com/archives/2004/05/10/rounding-worksheet-funtions/</link>
	<description>Daily posts of Excel tips…and other stuff</description>
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		<title>By: ghada</title>
		<link>http://www.dailydoseofexcel.com/archives/2004/05/10/rounding-worksheet-funtions/#comment-13581</link>
		<dc:creator>ghada</dc:creator>
		<pubDate>Wed, 08 Jun 2005 12:03:00 +0000</pubDate>
		<guid isPermaLink="false">http://www.dailydoseofexcel.com/?p=533#comment-13581</guid>
		<description>&lt;p&gt;Could you please explain how round function is used in time sheets to calculate the time in and out of employees??&lt;/p&gt;
&lt;p&gt;thanks&lt;/p&gt;
</description>
		<content:encoded><![CDATA[<p>Could you please explain how round function is used in time sheets to calculate the time in and out of employees??</p>
<p>thanks</p>
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	<item>
		<title>By: AmonRa</title>
		<link>http://www.dailydoseofexcel.com/archives/2004/05/10/rounding-worksheet-funtions/#comment-11355</link>
		<dc:creator>AmonRa</dc:creator>
		<pubDate>Sun, 24 Apr 2005 01:38:00 +0000</pubDate>
		<guid isPermaLink="false">http://www.dailydoseofexcel.com/?p=533#comment-11355</guid>
		<description>&lt;p&gt;But I haven&#039;t seen any decent function to perform a rounding while eliminating the error between the &quot;sum of the rounded&quot; and the &quot;rounded sum&quot;, e.g. like the following table&lt;/p&gt;
&lt;p&gt;A       B       C&lt;br&gt;
descvaluerounded&lt;br&gt;
a1000.491001&lt;br&gt;
b1000.491001&lt;br&gt;
c1.49   1&lt;br&gt;
d1.49   1&lt;br&gt;
sum2003.962004&lt;/p&gt;
&lt;p&gt;I came with (cell C2, but copied down):&lt;br&gt;
{=ROUND(B2-((1/((ROUND(B2,0)-B2)/B2))/(SUM(1/((ROUND($B$2:$B$5,0)-$B$2:$B$5)/$B$2:$B$5)))*(SUM(ROUND($B$2:$B$5,0))-SUM($B$2:$B$5))),0)}&lt;/p&gt;
&lt;p&gt;which does the trick, but is a bit awkward.&lt;/p&gt;
&lt;p&gt;The basic idea is correcting the error on the values in a way that creates the least error on each individual value. &lt;/p&gt;
&lt;p&gt;Any suggestions for a more esthetically acceptable solution?&lt;/p&gt;
</description>
		<content:encoded><![CDATA[<p>But I haven&#8217;t seen any decent function to perform a rounding while eliminating the error between the &#8220;sum of the rounded&#8221; and the &#8220;rounded sum&#8221;, e.g. like the following table</p>
<p>A       B       C<br />
descvaluerounded<br />
a1000.491001<br />
b1000.491001<br />
c1.49   1<br />
d1.49   1<br />
sum2003.962004</p>
<p>I came with (cell C2, but copied down):<br />
{=ROUND(B2-((1/((ROUND(B2,0)-B2)/B2))/(SUM(1/((ROUND($B$2:$B$5,0)-$B$2:$B$5)/$B$2:$B$5)))*(SUM(ROUND($B$2:$B$5,0))-SUM($B$2:$B$5))),0)}</p>
<p>which does the trick, but is a bit awkward.</p>
<p>The basic idea is correcting the error on the values in a way that creates the least error on each individual value. </p>
<p>Any suggestions for a more esthetically acceptable solution?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Jamie Collins</title>
		<link>http://www.dailydoseofexcel.com/archives/2004/05/10/rounding-worksheet-funtions/#comment-2631</link>
		<dc:creator>Jamie Collins</dc:creator>
		<pubDate>Wed, 24 Nov 2004 14:02:00 +0000</pubDate>
		<guid isPermaLink="false">http://www.dailydoseofexcel.com/?p=533#comment-2631</guid>
		<description>&lt;p&gt;&quot;For most users, the ROUND function is pretty self explanatory.&quot;&lt;/p&gt;
&lt;p&gt;I was for me until I read:&lt;/p&gt;
&lt;p&gt;How To Implement Custom Rounding Procedures&lt;br&gt;
&lt;a href=&quot;http://support.microsoft.com/default.aspx?scid=kb;en-us;196652&quot; rel=&quot;nofollow&quot;&gt;http://support.microsoft.com/default.aspx?scid=kb;en-us;196652&lt;/a&gt;&lt;/p&gt;
&lt;p&gt;Now I always check the rounding assumptions of the function I&#039;m using.&lt;/p&gt;
&lt;p&gt;Jamie.&lt;/p&gt;
&lt;p&gt;&lt;/p&gt;
</description>
		<content:encoded><![CDATA[<p>&#8220;For most users, the ROUND function is pretty self explanatory.&#8221;</p>
<p>I was for me until I read:</p>
<p>How To Implement Custom Rounding Procedures<br />
<a href="http://support.microsoft.com/default.aspx?scid=kb;en-us;196652" rel="nofollow">http://support.microsoft.com/default.aspx?scid=kb;en-us;196652</a></p>
<p>Now I always check the rounding assumptions of the function I&#8217;m using.</p>
<p>Jamie.</p>
<p></p>
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